Free Topic-Wise General Studies MCQs
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Explanation: Start with fixed positions: A is on floor 5 (TCS) and C is on floor 1. Since D (HCL) cannot be on floors 2 or 3, and floor 5 is occupied, D must be on floor 4. E lives above C (floor 1) but below D (floor 4), so E is on floor 2 or 3. B must occupy the remaining floor. B lives immediately below the Infosys employee, so the Infosys employee is directly above B. If E were on floor 2, then B would be on floor 3, making the Infosys employee on floor 4—but D on floor 4 works at HCL. Therefore E is on floor 3, making B on floor 2. The Infosys employee is then on floor 3, so E works at Infosys. The Wipro employee must be on an even floor (2 or 4); since D is on floor 4 (HCL), B on floor 2 must work at Wipro. The TechM employee must be on an odd floor below floor 5 (floor 1 or 3); since E on floor 3 is Infosys, C on floor 1 must work at TechM, which satisfies the constraint that C does not work at Wipro. Finally, Infosys (floor 3) is on a higher floor than Wipro (floor 2), satisfying the last constraint.
Explanation: Establish fixed positions: P is on floor 6 (White) and R is on floor 1. Since S (Green) cannot be on floors 2, 3, or 4, and floor 6 is occupied, S must be on floor 5. T must be above R (floor 1) but below Q, so T is on floor 2, 3, or 4. Q is immediately below the Red lover, so Red is above Q. The Blue lover must be on an even floor (2, 4, or 6); since P is White on floor 6, Blue is on floor 2 or 4. Testing T on floor 2: if T is Blue on floor 2, Q must be on floor 3 or 4 (since Q is above T and below the Red lover). If Q is on floor 3, the Red lover is on floor 4 (U). The Yellow lover must be on an odd floor below floor 6 (floor 1, 3, or 5); since S is Green on floor 5 and R is on floor 1, Yellow is on floor 1 or 3. If R is Yellow on floor 1, Q on floor 3 must be Black (the only remaining color for that position). The Black lover must be below Green (floor 5), and Q on floor 3 satisfies this constraint.
Explanation: Begin with fixed assignments: Physics is on Saturday and History is on Monday. Chemistry is immediately after Math, and Geography is after Chemistry but before Saturday, creating a chain: Math → Chemistry → Geography. This chain requires three ordered days before Saturday. Testing Math on Tuesday and Chemistry on Wednesday: Geography must then be on Thursday or Friday. If Geography were on Thursday, Biology would need to be on Friday (since Biology cannot be on Monday or Wednesday, and Tuesday is Math, Thursday is Geography); however, the constraint states that Thursday is not Geography. Therefore Geography is on Friday, making Biology on Thursday. The constraint that Tuesday is not Chemistry is satisfied (Math is on Tuesday), and the constraint that Thursday is not Geography is satisfied (Biology is on Thursday).
Explanation: Begin with fixed assignments: A works on Friday and D works on Monday. C cannot work on Monday or Thursday, so C must work on Tuesday or Wednesday. B works on the day immediately before C, so if C works on Tuesday, B works on Monday; however, D already works on Monday. Therefore C must work on Wednesday, making B work on Tuesday. E must work after B but before Friday, so E works on Thursday. The constraint that Wednesday is not B is satisfied (C works on Wednesday), and the constraint that Monday is not E is satisfied (D works on Monday). This gives the schedule: D on Monday, B on Tuesday, C on Wednesday, E on Thursday, and A on Friday.
Explanation: Start with fixed assignments: Rajdhani runs on Thursday and Garib Rath runs on Wednesday. Duronto cannot run on Monday or Wednesday, so with Thursday occupied by Rajdhani, Duronto must run on Tuesday. Shatabdi runs on the day immediately before Duronto, so Shatabdi runs on Monday. The constraint that Tuesday is not Shatabdi is satisfied (Duronto runs on Tuesday), and the constraint that Wednesday is not Rajdhani is satisfied (Garib Rath runs on Wednesday).
Explanation: Start with fixed positions: A is at position 1 (1kg) and C is at position 5. Since D cannot be at positions 2 or 4, and position 1 is occupied, D must be at position 3. E must be between A (position 1) and B, so E is at position 2 or 4. B is immediately below the 4kg box, so the 4kg box is above B. Testing E at position 2: B must be below E, so B is at position 3, 4, or 5; since D is at position 3 and C is at position 5, B must be at position 4. This makes the 4kg box at position 5 (C), which satisfies the constraint that C is not 5kg. The 3kg box must be at an even position (2 or 4); since B is at position 4, E at position 2 must be 3kg. The 5kg box must be above the 2kg box, so the 5kg box is at position 1, 2, or 3 and the 2kg box is below it; since A is 1kg at position 1 and E is 3kg at position 2, D at position 3 must be 5kg, making B at position 4 the 2kg box.
Explanation: First place the fixed positions: A is on floor 5 (age 60) and C is on floor 2. Since D (age 40) cannot be on floors 2 or 4, and floor 5 is occupied, D must be on floor 1 or 3. The constraint E > B and A > E means E is between A and B. If D is on floor 3, then E must be on floor 1 or 4; since E must be above B, testing E on floor 4 places B on floor 1, 2, or 3. With C on floor 2 and D on floor 3, B would be on floor 1. But B lives immediately above the 20-year-old, which would require the 20-year-old to be on floor 0—impossible. Therefore D must be on floor 1 (age 40). With D on floor 1, E must be on floor 3 or 4. If E is on floor 3, B must be on floor 1 or 2; floor 1 is D and floor 2 is C, so B would have to be on floor 2, but C is already there. Therefore E is on floor 4. B must be below E, so B is on floor 1, 2, or 3; floor 1 is D and floor 2 is C, so B is on floor 3. B lives immediately above the 20-year-old, so C on floor 2 is 20. The 30-year-old must be on an even floor (2 or 4); since C is 20 on floor 2, E on floor 4 must be 30. The 50-year-old must be on an odd floor below floor 5 (floor 1 or 3); since D on floor 1 is 40, B on floor 3 must be 50. Thus the person on floor 1 is 40 years old.
Explanation: Start with fixed positions: A is at position 1 (2kg) and C is at position 5. Since D cannot be at positions 2 or 4, and position 1 is occupied, D must be at position 3. Box E must be between A (position 1) and B, so E is at position 2 or 4. If E were at position 4, B would have to be below it at position 5, but C is already at position 5; therefore E is at position 2. This places B at position 4 (the only remaining spot below E). Since B is immediately below the 8kg box, D at position 3 must be 8kg. The 6kg box must be at an even position (2 or 4). Since B does not weigh 10kg, if B at position 4 were 4kg then E and C would need to be 6kg and 10kg; but C cannot be 10kg and position 5 is odd so it cannot hold the 6kg weight. Therefore B at position 4 must be 6kg. The remaining weights for E (position 2) and C (position 5) are 4kg and 10kg. Since C is not 10kg, C is 4kg and E is 10kg. The 10kg box (position 2) is above the 4kg box (position 5), satisfying the final constraint.
Explanation: Start with fixed assignments: P attends on Friday and S attends on Monday. R cannot attend on Monday or Thursday, so R must attend on Tuesday or Wednesday. Q attends on the day immediately after R, so if R attends on Tuesday, Q attends on Wednesday. T must attend after Q but before Friday, so T attends on Thursday. The constraint that Thursday is not Q is satisfied (T attends on Thursday), and the constraint that Monday is not T is satisfied (S attends on Monday). This gives the schedule: S on Monday, R on Tuesday, Q on Wednesday, T on Thursday, and P on Friday.
Explanation: Establish fixed positions: P is at position 1 (Red) and R is at position 5. Since S cannot be at positions 2 or 4, and position 1 is occupied, S must be at position 3. Box T must be between P (position 1) and Q, so T is at position 2, forcing Q to be at position 4. Because Q is immediately below the Green box, S at position 3 must be Green. The Blue box must be at an even position (2 or 4). The Yellow box must be above the Black box (position 5), so Yellow must be at position 2 or 4. Because the Blue box is in a higher position than the Yellow box, T at position 2 must be Blue, and Q at position 4 must be Yellow. R at position 5 is Black. Therefore, Q is the Yellow box.
Explanation: Start with fixed positions: P is at position 1 (A) and R is at position 5. Since S cannot be at positions 2 or 4, and position 1 is occupied, S must be at position 3. T must be below P (position 1) but above Q, so T is at position 2 or 4. Q is immediately above the B box, so B is below Q. Q must be at position 2, 3, 4, or 5; since S is at position 3 and R is at position 5, Q is at position 2 or 4. If T were at position 4, Q would have to be below T, so Q would be at position 5 (R), but then B would be below R, which is impossible. Therefore T is at position 2, making Q at position 4 (since Q must be below T and above R). This places B at position 5 (R), which satisfies the constraint that R is not E. The D box must be at an odd position below position 5 (position 1 or 3); since P is at position 1 with A, S at position 3 must be D. The E box must be above D (position 3), so it is at position 1 or 2; since P is at position 1 with A, T at position 2 must be E. The C box must be at an even position (2 or 4); since T is at position 2 with E, Q at position 4 must be C.
Explanation: Begin with fixed positions: A is at position 1 (11) and C is at position 6. Since D cannot be at positions 2, 3, or 5, and position 1 is occupied, D must be at position 4. The box with 66 must be to the left of the box with 44. Since C at position 6 is not 66, and D at position 4 is not 44, the 44 box can only be at position 5 or 6. If 44 were at position 5 (Box B), then B would need to be immediately to the right of the 33 box, forcing 33 into position 4 (Box D). With D=33, the 66 box would need to be at position 2 or 3 to remain left of 44. The 22 box must be at an even position left of the 66 box; if 66 were at position 2, 22 would need to be at position 1, but A=1 holds 11. If 66 were at position 3, 22 would need to be at position 2, but then the 55 box would have no valid odd position left (positions 1 and 3 would be taken by 11 and 66, and position 5 by 44). Therefore 44 cannot be at position 5, so C at position 6 must contain 44.
Explanation: Begin with fixed positions: W is at position 1 (A) and Y is at position 4. Since Z cannot be at position 2, Z must be at position 3. X is immediately to the left of the C box, so X is at position 2 and Z at position 3 must contain C, which satisfies the constraint that Z does not contain B. The D box must be to the left of the C box (position 3), so it is at position 1 or 2; since W is at position 1 with A, X at position 2 must contain D. The B box must be at an even position (2 or 4); since X is at position 2 with D, Y at position 4 must contain B, which satisfies the constraint that Y does not contain D.
Explanation: Start with fixed assignments: P works on Friday and S works on Monday. R cannot work on Monday or Thursday, so R must work on Tuesday or Wednesday. Q works on the day immediately after R, so if R works on Tuesday, Q works on Wednesday. T must work after Q but before Friday, so T works on Thursday. The constraint that Tuesday is not Q is satisfied (R works on Tuesday), and the constraint that Monday is not T is satisfied (S works on Monday). This gives the schedule: S on Monday, R on Tuesday, Q on Wednesday, T on Thursday, and P on Friday.
Explanation: Start with fixed positions: P is on floor 5 (190 cm) and R is on floor 1. Since S (160 cm) cannot be on floors 2 or 3, and floor 5 is occupied, S must be on floor 4. The sum of floors for the 150 cm and 160 cm persons equals 6; with S on floor 4 (160 cm), the 150 cm person must be on floor 2. T must be below P (floor 5) but above Q, so T is on floor 2 or 3; since floor 2 is occupied by the 150 cm person, T must be on floor 3. Q must be below T (floor 3), so Q is on floor 2 (since R is on floor 1). Q is immediately below the 170 cm person, so T on floor 3 must be 170 cm. The 180 cm person must be on an odd floor below floor 5 (floor 1 or 3); since T is 170 cm on floor 3, R on floor 1 must be 180 cm, which satisfies the constraint that R is not 150 cm.
Explanation: Establish fixed positions: J is on floor 6 (Apple), L is on floor 1, N is on floor 2 (Mango), and M is on floor 5 (Orange). Since K cannot be on floor 3 and floors 1, 2, 5, and 6 are occupied, K must be on floor 4. K lives immediately above the Banana lover, so O on floor 3 must like Banana. The Grapes lover must be on an odd floor below floor 6 (floor 1, 3, or 5); since O on floor 3 likes Banana and M on floor 5 likes Orange, L on floor 1 must like Grapes. The only remaining fruit is Papaya, which must go to K on floor 4. This satisfies the constraint that Papaya (floor 4) is on a lower floor than Orange (floor 5).
Explanation: Start with fixed assignments: Rajdhani runs on Thursday and Garib Rath runs on Monday. Duronto cannot run on Monday or Wednesday, so with Thursday occupied by Rajdhani, Duronto must run on Tuesday. Shatabdi runs on the day immediately after Duronto, so Shatabdi runs on Wednesday. The constraint that Tuesday is not Shatabdi is satisfied (Duronto runs on Tuesday), and the constraint that Wednesday is not Rajdhani is satisfied (Shatabdi runs on Wednesday).
Explanation: Begin with fixed positions: P is at position 1 (Book) and R is at position 5. Since S (Phone) cannot be at positions 2 or 3, and position 1 is occupied, S must be at position 4. The Watch must be to the left of the Phone (position 4), so it is at position 2 or 3. Q is immediately to the right of the Watch; if the Watch were at position 3, Q would be at position 4 (S), but S has the Phone. Therefore the Watch is at position 2, making Q at position 3. T must be between P (position 1) and Q (position 3), so T is at position 2 with the Watch. The Pen and Wallet must both be at odd positions (1, 3, or 5); since P is at position 1 with the Book, the Pen and Wallet are at positions 3 and 5. Since R at position 5 does not have the Wallet, Q at position 3 must have the Wallet, and R at position 5 must have the Pen.
Explanation: Begin with fixed assignments: A visits on Friday and D visits on Wednesday. C cannot visit on Monday or Friday, so C must visit on Tuesday or Thursday. B visits on the day immediately before C, so if C visits on Tuesday, B visits on Monday. E must visit after C but before Friday, so with D on Wednesday, E must visit on Thursday. The constraint that Tuesday is not B is satisfied (C visits on Tuesday), and the constraint that Wednesday is not E is satisfied (D visits on Wednesday). This gives the schedule: B on Monday, C on Tuesday, D on Wednesday, E on Thursday, and A on Friday.
Explanation: Begin with fixed assignments: Event A is in June and Event D is in February. Event C cannot be in January or March, so with February and June occupied, C must be in April or May. If C is in May, B would be in June, but A is already in June. Therefore C is in April, making B in May. Event E must be after February but before June, so it must be in March. The constraint that April is not B is satisfied (C is in April), and the constraint that May is not E is satisfied (B is in May). The remaining event, F, is in January.
Explanation: Begin with fixed positions: W is at position 1 (5kg) and Y is at position 4. Since Z cannot be at position 3, Z must be at position 2. Z is not 10kg, so Z at position 2 must be 15kg (since X is immediately below the 15kg box, and the only position above X is position 2). This places X at position 3. The 10kg box must be at an even position (2 or 4); since Z is 15kg at position 2, Y at position 4 must be 10kg, which satisfies the constraint that Y is not 20kg. The 20kg box must be above the 10kg box (position 4), so it must be at position 1, 2, or 3; since W is 5kg at position 1 and Z is 15kg at position 2, X at position 3 must be 20kg.
Explanation: Start with fixed assignments: Math is in the 5th period and Hindi is in the 1st period. English cannot be in the 1st or 3rd period, so with the 5th period occupied by Math, English must be in the 2nd or 4th period. If English were in the 4th period, Science would be in the 5th period, but Math is already in the 5th period. Therefore English is in the 2nd period, making Science in the 3rd period. SST must be after English (2nd period) but before Math (5th period), so SST must be in the 4th period. The constraint that the 4th period is not Science is satisfied (SST is in the 4th period), and the constraint that the 1st period is not SST is satisfied (Hindi is in the 1st period).
Explanation: Start with absolute positions: M is on floor 6 and O is on floor 1. Since P (Chemistry) cannot be on floors 2, 3, or 5, and floor 6 is occupied, P must be on floor 4. Q lives above N but below M (floor 6), so Q is on floor 3 or 5. The Biology student must be on an even floor (2, 4, or 6); since P is on floor 4 with Chemistry, Biology is on floor 2 or 6. The Geography student must be on an even floor below floor 4, which is floor 2. Therefore Biology must be on floor 6 (M). The Physics student must be on an odd floor above floor 4 (floor 5 or 7); since M is on floor 6, Q on floor 5 must study Physics. N lives immediately below the Math student, so the Math student is directly above N. With Q on floor 5 and P on floor 4, the Math student must be on floor 3, making N on floor 2. Since Geography must be on floor 2, N on floor 2 studies Geography. O on floor 1 studies History, which satisfies the constraint that O does not study Biology.
Explanation: Start with fixed positions: A is on floor 5 (Wallet) and C is on floor 1. Since D (Pen) cannot be on floors 2 or 3, and floor 5 is occupied, D must be on floor 4. B lives immediately above the Phone owner, so the Phone is below B. E must be below A (floor 5) but above B, so E is on floor 2 or 3, and B is below E. Testing B on floor 2: E must be above B and below floor 5, so E is on floor 3 (since D is on floor 4). This places the Phone on floor 1 (C), which satisfies the constraint that C does not have the Book. The Watch must be on an odd floor below floor 5 (floor 1 or 3); since C is on floor 1 with the Phone, E on floor 3 must have the Watch. The Book must be on an even floor (2 or 4); since D is on floor 4 with the Pen, B on floor 2 must have the Book.
Explanation: Begin with fixed positions: M is at position 1 (Apple) and O is at position 4. Since P cannot be at position 2 and does not contain Banana, and position 1 is occupied, P must be at position 3. This places N at position 2. N is immediately to the left of the Mango box, so P at position 3 must contain Mango, which satisfies the constraint that P does not contain Banana. The Banana box must be at an even position (2 or 4); since O at position 4 cannot contain Mango but could contain Banana, and the Orange box must be to the left of the Mango box (position 3), Orange must be at position 1 or 2. Since M at position 1 contains Apple, N at position 2 must contain Orange. This leaves O at position 4 containing Banana, which satisfies the even-position constraint for Banana.
Explanation: Begin with fixed positions: A is at position 1 (10) and C is at position 5. Since D cannot be at positions 2 or 4, and position 1 is occupied, D must be at position 3. E must be between A (position 1) and B, so E is at position 2 or 4. B is immediately to the right of the 30 box, so 30 is to the left of B. B must be at position 2, 3, 4, or 5; since D is at position 3 and C is at position 5, B is at position 2 or 4. If E were at position 4, B would have to be at position 5 (C), but then 30 would be at position 4 (E), and D at position 3 would have no valid number. Therefore E is at position 2, making B at position 4 (since B must be to the right of E). This places 30 at position 3 (D), which satisfies the constraint that D does not contain 20. The 40 box must be at an odd position (1, 3, or 5); since A is at position 1 with 10 and D is at position 3 with 30, C at position 5 must contain 40. The 50 box must be to the left of 40 (position 5), so it is at position 1, 2, 3, or 4; with A at position 1 (10), D at position 3 (30), and B at position 4, E at position 2 must contain 50. The 20 box must be at an even position (2 or 4); since E is at position 2 with 50, B at position 4 must contain 20.
Explanation: First establish fixed positions: V is on floor 5 and X is on floor 1. Since Y cannot be on floors 2 or 3, and floors 1 and 5 are occupied, Y must be on floor 4. The constraint 'Z lives below V but above W' creates the order V > Z > W. With Y on floor 4, Z must be on floor 3 (the only position between V and W that allows W to be lower). This places W on floor 2. Since W lives immediately above the person who likes Red, the person on floor 1 (X) likes Red. The Blue lover must be on an even floor (2 or 4); since Y on floor 4 likes Green, W on floor 2 likes Blue. Black must be on an odd floor below floor 5 (floor 1 or 3); since X on floor 1 likes Red, Z on floor 3 likes Black. The only remaining color, Yellow, goes to V on floor 5.
Explanation: Begin with fixed positions: W is at position 1 (5 coins) and Y is at position 4. Since Z cannot be at position 2, Z must be at position 3. X is immediately to the left of the 15-coin box, so X is at position 2 and Z at position 3 must have 15 coins, which satisfies the constraint that Z does not have 10 coins. The 20-coin box must be to the left of the 15-coin box (position 3), so it is at position 1 or 2; since W is at position 1 with 5 coins, X at position 2 must have 20 coins. The 10-coin box must be at an even position (2 or 4); since X is at position 2 with 20 coins, Y at position 4 must have 10 coins, which satisfies the constraint that Y does not have 20 coins.
Explanation: Establish fixed positions: J is on floor 6 (Doctor) and L is on floor 1. Since M (Teacher) cannot be on floors 2, 3, or 4, and floor 6 is occupied, M must be on floor 5. N must be above L (floor 1) but below K, so N is on floor 2, 3, or 4. K is immediately above the Lawyer, so the Lawyer is below K. Testing N on floor 2: K must be above N, so K is on floor 3, 4, 5, or 6; with M on floor 5 and J on floor 6, K must be on floor 3 or 4. If K is on floor 3, the Lawyer is on floor 2 (N). The Engineer must be on an even floor (2, 4, or 6); since N is the Lawyer on floor 2 and J is the Doctor on floor 6, the Engineer must be on floor 4. The Artist must be on an odd floor below floor 6 (floor 1, 3, or 5); with L on floor 1 and M on floor 5 (Teacher), K on floor 3 must be the Artist or Nurse. The Nurse must be below the Teacher (floor 5), so the Nurse is on floor 1, 2, 3, or 4; with L on floor 1, N on floor 2 (Lawyer), and the Engineer on floor 4, K on floor 3 must be the Nurse. This leaves the Artist for L on floor 1, which satisfies the constraint that L is not the Engineer.
Explanation: Begin with fixed positions: M is at position 1 (Red) and O is at position 4. Since P cannot be at position 2 and is not Red, and position 4 is occupied, P must be at position 3. N is immediately to the left of the Green box, so N is at position 2 and P at position 3 must be Green. The Green box must be to the left of the Yellow box, so Yellow is at position 4 (O). The Blue box must be at an even position (2 or 4); since O is Yellow at position 4, N at position 2 must be Blue, which satisfies the constraint that O is not Blue.
Explanation: Start with fixed assignments: Math is in the 5th period and Hindi is in the 1st period. English cannot be in the 1st or 3rd period, so with the 5th period occupied by Math, English must be in the 2nd or 4th period. If English were in the 4th period, Science would be in the 5th period, but Math is already in the 5th period. Therefore English is in the 2nd period, making Science in the 3rd period. SST must be after Science (3rd period) but before Math (5th period), so SST must be in the 4th period. The constraint that the 4th period is not Science is satisfied (SST is in the 4th period), and the constraint that the 1st period is not SST is satisfied (Hindi is in the 1st period).
Explanation: Start with absolute positions: A is on floor 4 and C is on floor 1. Since D does not live on floor 2 and floors 1 and 4 are taken, D must be on floor 3. The statement 'B lives immediately below the doctor' means the doctor lives on floor 3, so D is the doctor. This forces B onto floor 2. The engineer must be on an even floor (2 or 4). The lawyer lives above the teacher, and C (floor 1) is not the lawyer, so the lawyer is on floor 2 or 4. If B (floor 2) were the lawyer, the teacher would have to be on floor 1 (C), making A (floor 4) the engineer—this is valid. If A (floor 4) were the lawyer, the teacher would be on floor 1, 2, or 3; C is not the lawyer but could be the teacher, making B the engineer—also valid. Therefore only 'D is the doctor and lives on floor 3' is true in every valid arrangement.
Explanation: Start with fixed positions: P is on floor 5 (Car) and R is on floor 1. Since S (Bike) cannot be on floors 2 or 3, and floor 5 is occupied, S must be on floor 4. T lives above R (floor 1) but below Q, so T is on floor 2 or 3 and Q is above T. The Bus owner must be on an even floor (2 or 4); since S is on floor 4 with a Bike, T on floor 2 must have the Bus. Q lives immediately above the Bus owner, so Q is on floor 3. The Train owner must be on an odd floor below floor 5 (floor 1 or 3); since R on floor 1 does not have a Train, Q on floor 3 must have the Train. The Scooter owner must be on a lower floor than the Bike owner (floor 4); with the Bus on floor 2 and the Train on floor 3, R on floor 1 must have the Scooter.
Explanation: Start with fixed assignments: Reading is at 2pm and Testing is at 8am. Coding cannot be at 8am or 12pm, so with 2pm occupied by Reading, Coding must be at 10am. Writing is at the slot immediately after Coding, so Writing is at 12pm. The constraint that the task at 10am is not Writing is satisfied (Coding is at 10am), and the constraint that the task at 12pm is not Reading is satisfied (Writing is at 12pm).
Explanation: Start with fixed assignments: A visits on Friday and D visits on Monday. C cannot visit on Monday or Wednesday, so C must visit on Tuesday or Thursday. B visits on the day immediately after C, so if C visits on Tuesday, B visits on Wednesday. E must visit after B but before Friday, so E visits on Thursday. The constraint that Thursday is not B is satisfied (E visits on Thursday), and the constraint that Monday is not E is satisfied (D visits on Monday). This gives the schedule: D on Monday, C on Tuesday, B on Wednesday, E on Thursday, and A on Friday.
Explanation: Establish fixed positions: P is at position 1 (Red) and R is at position 6. Since S (Yellow) cannot be at positions 2, 3, or 5, and position 1 is occupied, S must be at position 4. Box T must be below P (position 1) but above Q, so T is at position 2 or 3 with Q placed higher than T. Q is immediately below the Green box, so the Green box is directly above Q. Testing T at position 2: Q must be above T, so Q is at position 3, 4, 5, or 6; with S at position 4 and R at position 6, Q must be at position 3 or 5. If Q were at position 5, the Green box would be at position 4 (S), but S is Yellow. Therefore Q is at position 3, making the Green box at position 2 (T). The Black box must be above Yellow (position 4), so it is at position 1, 2, or 3; since P is Red at position 1 and T is Green at position 2, Q at position 3 must be Black. The Blue box must be at an even position (2, 4, or 6); since T is Green at position 2 and S is Yellow at position 4, R at position 6 must be Blue, which satisfies the constraint that R is not White. The White box must be at an odd position left of position 6 (position 1, 3, or 5); since P is Red at position 1 and Q is Black at position 3, U at position 5 must be White.
Explanation: Begin with absolute positions: M is on floor 4 (180 cm) and O is on floor 1. Since P cannot be on floor 2 and floor 4 is occupied, P must be on floor 1 or 3; with O on floor 1, P is on floor 3. The 160 cm person must be on an even floor (2 or 4); since M is 180 cm on floor 4, N on floor 2 must be 160 cm. The 170 cm person must be above the 160 cm person, so on floor 3 or 4; since M is 180 cm on floor 4, P on floor 3 must be 170 cm. N lives immediately above the 150 cm person, so O on floor 1 is 150 cm, which satisfies the constraint that O is not 170 cm.
Explanation: Begin with fixed assignments: Event A is in June and Event D is in February. Event C cannot be in January or March, so with February and June occupied, C must be in April or May. If C is in May, B would be in June, but A is already in June. Therefore C is in April, making B in May. Event E must be after February but before June, so it must be in March. The constraint that April is not B is satisfied (C is in April), and the constraint that May is not E is satisfied (B is in May). The remaining event, F, must be in January.
Explanation: Establish fixed positions: W is on floor 6 (â‚ą80k) and Y is on floor 1. Since Z (â‚ą60k) cannot be on floors 2, 3, or 4, and floor 6 is occupied, Z must be on floor 5. The sum of floors for â‚ą30k and â‚ą60k earners equals 9; with Z on floor 5 (â‚ą60k), the â‚ą30k earner must be on floor 4. A must be above Y (floor 1) but below X, so A is on floor 2 or 3. X is immediately above the â‚ą50k earner, so the â‚ą50k earner is below X. Testing A on floor 3: X must be above A, so X is on floor 4, 5, or 6; with Z on floor 5 and W on floor 6, X must be on floor 4 (â‚ą30k). This makes the â‚ą50k earner on floor 3 (A), since X is immediately above A. The â‚ą40k earner must be on an even floor (2, 4, or 6); with X on floor 4 (â‚ą30k) and W on floor 6 (â‚ą80k), B on floor 2 must earn â‚ą40k. The â‚ą70k earner must be on an odd floor below floor 6 (floor 1, 3, or 5); with A on floor 3 (â‚ą50k) and Z on floor 5 (â‚ą60k), Y on floor 1 must earn â‚ą70k, which satisfies the constraint that Y does not earn â‚ą30k.
Explanation: Establish fixed positions first: J is on floor 4 earning â‚ą40k, and L is on floor 1. Since M (â‚ą50k) cannot be on floors 2 or 4, and floor 5 is occupied, M must be on floor 3 or 5. The sum of floors for â‚ą20k and â‚ą50k earners equals 7; if M (â‚ą50k) is on floor 5, the â‚ą20k earner must be on floor 2 (since 5+2=7). This places K immediately above the â‚ą20k earner, so K is on floor 3, which means M must be on floor 5. N lives below J (floor 4) but above the â‚ą30k earner; with floor 2 occupied by the â‚ą20k earner, N must be on floor 2, making the â‚ą30k earner on floor 1 (L). The remaining salary, â‚ą60k, goes to K on floor 3, which satisfies the odd-floor constraint for the highest salary.
Explanation: Begin with fixed assignments: Hindi is on Friday and Science is on Monday. Math cannot be on Monday or Wednesday, so Math must be on Tuesday or Thursday. English is on the day immediately after Math, so if Math is on Tuesday, English is on Wednesday. SST must be after English but before Friday, so SST is on Thursday. The constraint that Thursday is not English is satisfied (SST is on Thursday), and the constraint that Monday is not SST is satisfied (Science is on Monday). This gives the schedule: Science on Monday, Math on Tuesday, English on Wednesday, SST on Thursday, and Hindi on Friday.
Explanation: In a seven-floor building, only floor 4 has equal floors above and below it, so T is on floor 4. S (Math) cannot be on floors 2, 3, or 5, and with floors 1 and 7 occupied, S must be on floor 6. U lives between R (floor 1) and T (floor 4), so U is on floor 2 or 3. Q lives immediately above the Chemistry student, and Chemistry must be on an odd floor. If Q were on floor 6, Chemistry would be on floor 5—but History must also be on an odd floor above 4 (floor 5 or 7), and P already occupies floor 7 with Physics, forcing History onto floor 5 and creating a conflict. Therefore Q is on floor 2, making R on floor 1 the Chemistry student. This forces U onto floor 3. History must be on floor 5, so V is on floor 5 studying History. Biology must be on an even floor (2, 4, or 6); since S is on floor 6 with Math, Biology is on floor 2 or 4. If Biology were on floor 2 (Q), then Geography and English would need to occupy floors 3 and 4, with Geography on an even floor—meaning T on floor 4 would study Geography and U on floor 3 would study English. But this violates the constraint that Geography must be on a lower floor than English (4 is not below 3). Therefore Biology is on floor 4 (T), leaving Geography and English for floors 2 and 3. Geography must be on an even floor, so Q on floor 2 studies Geography, and U on floor 3 studies English. This satisfies Geography (2) being below English (3).
Explanation: Begin with fixed assignments: Action is on Friday, Horror is on Monday, and Romance is on Thursday. Drama cannot be on Monday or Wednesday, so with Thursday and Friday occupied, Drama must be on Tuesday. Comedy is on the day immediately after Drama, so Comedy is on Wednesday. The constraint that Tuesday is not Comedy is satisfied (Drama is on Tuesday), and the constraint that Thursday is not Action is satisfied (Romance is on Thursday).
Explanation: Begin with fixed positions: P is at position 1 (12) and R is at position 5. Since S cannot be at positions 2 or 4, and position 1 is occupied, S must be at position 3. T must be between P (position 1) and Q, so T is at position 2 or 4. Q is immediately to the right of the 36 box, so 36 is to the left of Q. Q must be at position 2, 3, 4, or 5; since S is at position 3 and R is at position 5, Q is at position 2 or 4. If T were at position 4, Q would have to be at position 5 (R), but then 36 would be at position 4 (T), and S at position 3 would have no valid number. Therefore T is at position 2, making Q at position 4 (since Q must be to the right of T). This places 36 at position 3 (S), which satisfies the constraint that S does not contain 48. The 48 box must be at an odd position (1, 3, or 5); since P is at position 1 with 12 and S is at position 3 with 36, R at position 5 must contain 48, which satisfies the constraint that R does not contain 60. The 60 box must be to the left of 48 (position 5), so it is at position 1, 2, 3, or 4; with P at position 1 (12), S at position 3 (36), and Q at position 4, T at position 2 must contain 60. The 24 box must be at an even position (2 or 4); since T is at position 2 with 60, Q at position 4 must contain 24.
Explanation: Start with fixed positions: M is at position 1 (Apple) and O is at position 5. Since P cannot be at positions 2 or 4, and position 1 is occupied, P must be at position 3. Box Q must be between M (position 1) and N, so Q is at position 2 or 4. If Q were at position 4, N would be at position 5 (O), but N must be immediately below the Mango box, which would place the Mango box at position 5; however, O does not contain Banana but could contain Mango, and P at position 3 would then need to contain Orange, violating the constraint that P does not contain Orange. Therefore Q is at position 2, making N at position 4 (since N must be below Q and P is at position 3). N is immediately below the Mango box, so P at position 3 must contain Mango. The Banana box must be at an even position (2 or 4); since N is at position 4 and P is at position 3 with Mango, Q at position 2 must contain Banana. The Grapes box must be above the Orange box, so Grapes is at position 4 and Orange is at position 5; since O at position 5 is not Banana, O must contain Orange and N at position 4 must contain Grapes.
Explanation: Start with fixed positions: A is on floor 4 (BMW) and C is on floor 1. Since D cannot be on floor 2 and floor 4 is occupied, D must be on floor 1 or 3; with C on floor 1, D is on floor 3. B lives immediately above the Toyota owner, so the Toyota is below B. B must be on floor 2 or 3; since D is on floor 3, B is on floor 2, making C on floor 1 the Toyota owner. The Honda owner must be on an even floor (2 or 4); since A is on floor 4 with BMW, B on floor 2 must have Honda. The Maruti owner must be on a higher floor than the Honda owner (floor 2), so Maruti is on floor 3 or 4; since A is on floor 4 with BMW, D on floor 3 must have Maruti, which satisfies the constraint that D does not have Honda.
Explanation: Start with fixed positions: P is on floor 5 (Black) and R is on floor 1. Since S (Blue) cannot be on floors 2 or 3, and floor 5 is occupied, S must be on floor 4. Box T must be below P (floor 5) but above Q, so T is on floor 2 or 3. If T were on floor 2, Q would have to be on floor 1 (R), but Q must be immediately below the person who likes Red, which would place the Red lover on floor 2 (T), and then Q would need to be on floor 1, conflicting with R. Therefore T is on floor 3, making Q on floor 2 (since Q must be below T and R is on floor 1). Q is immediately below the Red lover, so T on floor 3 must like Red. The Green lover must be on an even floor (2 or 4); since S is Blue on floor 4, Q on floor 2 must like Green. The Yellow lover must be on an odd floor (1, 3, or 5); since P is Black on floor 5 and T is Red on floor 3, R on floor 1 must like Yellow, which satisfies the constraint that R does not like Green.
Explanation: Begin with fixed assignments: A visits on Friday and D visits on Thursday. C cannot visit on Monday or Friday, so C must visit on Tuesday or Wednesday. B visits on the day immediately before C, so if C visits on Tuesday, B visits on Monday. E must visit after C but before Friday, so with D on Thursday, E must visit on Wednesday. The constraint that Tuesday is not B is satisfied (C visits on Tuesday), and the constraint that Thursday is not E is satisfied (D visits on Thursday). This gives the schedule: B on Monday, C on Tuesday, E on Wednesday, D on Thursday, and A on Friday.
Explanation: Start with fixed assignments: V attends on Friday and Y attends on Monday. X cannot attend on Monday or Tuesday, so X must attend on Wednesday or Thursday. W attends on the day immediately before X, so if X were on Thursday, W would be on Wednesday; Z must then attend after W but before V, which would require Z to attend on a day between Wednesday and Friday—only Thursday is available, but X is already on Thursday. Therefore X must attend on Wednesday, making W attend on Tuesday. Z must attend after Tuesday but before Friday, so Z attends on Thursday. The constraint that Thursday is not W is satisfied (Z attends on Thursday), and the constraint that Monday is not Z is satisfied (Y attends on Monday). This gives the schedule: Y on Monday, W on Tuesday, X on Wednesday, Z on Thursday, and V on Friday.
Explanation: Begin with fixed positions: M is on floor 5 (Ruler) and O is on floor 1. Since P (Eraser) cannot be on floors 2 or 3, and floor 5 is occupied, P must be on floor 4. Q must be below M (floor 5) but above N, so Q is on floor 2 or 3. N lives immediately above the Pencil owner, so the Pencil is below N. If Q were on floor 2, N would have to be on floor 1 (O), but N must be above the Pencil owner. Therefore Q is on floor 3, making N on floor 2 (since N must be below Q and above the Pencil owner on floor 1). This places the Pencil with O on floor 1, which satisfies the constraint that O does not have the Pen. The Sharpener must be on a floor between the Pencil (floor 1) and the Eraser (floor 4), so it is on floor 2 or 3; since N is on floor 2 and Q is on floor 3, and the Pen must be on an even floor (2 or 4), N on floor 2 must have the Pen, leaving Q on floor 3 with the Sharpener.
Explanation: Establish fixed positions: P is at position 1 (Red) and R is at position 6. Since S (Yellow) cannot be at positions 2, 3, or 5, and position 1 is occupied, S must be at position 4. Box T must be between P (position 1) and Q, so T is at position 2, 3, or 5. The Blue box must be at an even position (2, 4, or 6); since S is Yellow at position 4, Blue must be at position 2 or 6. The Black box must be left of Yellow (position 4), so it is at position 2 or 3. Testing T at position 2: Q must be to the right of T, so Q is at position 3, 5, or 6; since R is at position 6, Q is at position 3 or 5. Q is immediately right of the Green box, so if Q is at position 3, the Green box is at position 2 (T). This makes T Green, leaving Blue for position 6 (R). The Black box must be at position 2 or 3; since T is Green at position 2, Q at position 3 must be Black. The White box must be at an odd position left of position 6 (position 1, 3, or 5); since P is Red at position 1 and Q is Black at position 3, U at position 5 must be White.
Explanation: In a five-floor building, only floor 3 has exactly 2 floors above it and 2 floors below it, so E is on floor 3. A is on floor 5 (Hindi) and C is on floor 2. Since D (English) cannot be on floors 2, 3, or 5, and floor 5 is occupied, D must be on floor 1 or 4. B lives immediately below the Tamil speaker, so Tamil is above B. B must be on floor 1, 2, 4, or 5; since C is on floor 2, E is on floor 3, and A is on floor 5, B must be on floor 1 or 4. If B were on floor 4, the Tamil speaker would be on floor 5 (A), but A speaks Hindi. Therefore B is on floor 1, making the Tamil speaker on floor 2 (C). The Tamil speaker must be on an even floor (2 or 4); since D is on floor 4 with English, C on floor 2 must be the Tamil speaker, which satisfies the constraint that C does not speak Telugu. The Bengali speaker must be on an odd floor below floor 5 (floor 1 or 3); with B on floor 1 and E on floor 3, and Telugu must be below English (floor 4), E on floor 3 must speak Telugu and B on floor 1 must speak Bengali.
Explanation: Begin with fixed positions: Box A is at position 1 (Pen) and Box C is at position 2. Since Box D (Eraser) cannot be at positions 2 or 4, and position 1 is occupied, D must be at position 3 or 5. Box E must be below A (position 1) but above B, so E is at position 2, 3, or 4; since C is at position 2, E must be at position 3 or 4. If E were at position 4, B would have to be below E, leaving only position 5 for B; but then the Pencil would need to be at position 4 (E), and D would need to be at position 3, leaving no valid arrangement for the Sharpener constraint. Therefore E is at position 3 (Pencil), which places B at position 4 (since B is immediately below the Pencil at position 3). This leaves D at position 5 (Eraser). The Ruler must be above the Eraser (position 5), so it must be at position 2, 3, or 4; since E at position 3 has the Pencil and B at position 4 must have the Ruler (as C at position 2 cannot have it), Box C at position 2 must contain the Sharpener, which satisfies the even-position constraint.
Explanation: Begin with fixed assignments: Math is on Saturday and English is on Monday. Physics is immediately before Chemistry, and History is after Chemistry but before Saturday, creating a chain: Physics → Chemistry → History. This chain requires three consecutive or ordered days before Saturday. Testing Physics on Wednesday and Chemistry on Thursday: History must then be on Friday (the only day between Thursday and Saturday that satisfies the ordering). Biology cannot be on Monday or Wednesday, so with English on Monday, Physics on Wednesday, and Chemistry on Thursday, Biology must be on Tuesday. The constraint that Tuesday is not Physics is satisfied (Biology is on Tuesday), and the constraint that Thursday is not History is satisfied (Chemistry is on Thursday).
Explanation: Begin with fixed positions: V is on floor 5 (age 65) and X is on floor 1. Since Y (age 35) cannot be on floors 2 or 3, and floor 5 is occupied, Y must be on floor 4. Z must be below V (floor 5) but above W, so Z is on floor 2 or 3. The 25-year-old must be on an even floor (2 or 4); since Y is 35 on floor 4, the 25-year-old must be on floor 2. This means Z cannot be on floor 2 (as that would make Z 25 years old), so Z is on floor 3. W must be below Z (floor 3), so W is on floor 2 (since X is on floor 1). W is immediately below the 45-year-old, so Z on floor 3 must be 45 years old. The 55-year-old must be on an odd floor below floor 5 (floor 1 or 3); since Z is 45 on floor 3, X on floor 1 must be 55 years old, which satisfies the constraint that X is not 25.
Explanation: Begin with fixed positions: A is at position 1 (5) and C is at position 6. Since D cannot be at positions 2, 3, or 5, and position 1 is occupied, D must be at position 4. E must be between A (position 1) and B, so E is at position 2, 3, or 5. B is immediately to the right of the 20 box, so 20 is to the left of B. B must be at position 2, 3, 4, 5, or 6; since D is at position 4 and C is at position 6, B is at position 2, 3, or 5. The 15 box must be at an odd position left of position 6 (position 1, 3, or 5); since A is at position 1 with 5, 15 is at position 3 or 5. The 25 box must be to the left of the 15 box. Testing E at position 3 (15): B must be to the right of E, so B is at position 4, 5, or 6; since D is at position 4 and C is at position 6, B must be at position 5. This places 20 at position 4 (D), which satisfies the constraint that D does not contain 25. The 25 box must be to the left of 15 (position 3), so it is at position 2 (F). The 10 box must be at an even position (2, 4, or 6); since F is at position 2 with 25 and D is at position 4 with 20, C at position 6 must contain 10, which satisfies the constraint that C does not contain 30. The remaining number, 30, goes to B at position 5.
Explanation: Establish fixed positions: M is at position 1 (Apple) and O is at position 6. Since P (Banana) cannot be at positions 2, 3, or 5, and position 1 is occupied, P must be at position 4. Box Q must be between M (position 1) and N, so Q is at position 2, 3, or 5. The Orange box must be at an even position (2, 4, or 6); since P is Banana at position 4, Orange is at position 2 or 6. The Papaya box must be to the left of Banana (position 4), so it is at position 1, 2, or 3; since M is Apple at position 1, Papaya is at position 2 or 3. The Grapes box must be at an odd position left of position 6 (position 1, 3, or 5); since M is at position 1, Grapes is at position 3 or 5. Testing Q at position 2: N must be to the right of Q, so N is at position 3, 4, 5, or 6; since P is at position 4 and O is at position 6, N is at position 3 or 5. N is immediately to the right of the Mango box, so if N is at position 3, the Mango box is at position 2 (Q). This makes Q Mango, and with Papaya at position 2 or 3, N at position 3 must be Papaya. The Grapes box must be at position 3 or 5; since N is Papaya at position 3, the person at position 5 (R) must have Grapes. Orange must be at position 2 or 6; since Q is Mango at position 2, O at position 6 must be Orange, which satisfies the constraint that O is not Papaya.
Explanation: Start with fixed assignments: P attends at 3pm and S attends at 9am. R cannot attend at 9am or 1pm, so with 3pm occupied by P, R must attend at 11am. Q attends at the slot immediately after R, so Q attends at 1pm. The constraint that the person at 11am is not Q is satisfied (R is at 11am), and the constraint that the person at 1pm is not P is satisfied (Q is at 1pm).
Explanation: Begin with fixed assignments: Action is on Thursday and Horror is on Monday. Drama cannot be on Monday or Wednesday, so with Thursday occupied by Action, Drama must be on Tuesday. Comedy is on the day immediately after Drama, so Comedy is on Wednesday. The constraint that Tuesday is not Comedy is satisfied (Drama is on Tuesday), and the constraint that Wednesday is not Action is satisfied (Comedy is on Wednesday).
Explanation: Establish fixed positions: M is at position 1 (A) and O is at position 6. Since P (D) cannot be at positions 2, 3, or 5, and position 1 is occupied, P must be at position 4. Box Q must be between M (position 1) and N, so Q is at position 2, 3, or 5. The box with B must be to the left of D (position 4), so B is at position 2 or 3. The box with F must be at an odd position left of position 6 (position 1, 3, or 5); since M is at position 1 with A, F is at position 3 or 5. Testing Q at position 2: N must be to the right of Q, so N is at position 3, 5, or 6; since O is at position 6, N is at position 3 or 5. N is immediately to the right of the box with C, so if N were at position 5, C would be at position 4 (P), but P contains D. Therefore N is at position 3, making Q at position 2 contain C. The box with E must be at an even position (2, 4, or 6); since Q is at position 2 with C and P is at position 4 with D, O at position 6 must contain E. With B at position 2 or 3, and Q at position 2 with C, N at position 3 must contain B. This leaves F for position 5, which is occupied by R.