A train of length 150 m crosses a platform of length 350 m at 72 km/h. How many seconds does it take to completely cross the platform?
Explanation: Total distance = Length of train + Length of platform = 150 + 350 = 500 m. Speed = 72 km/h = 20 m/s. Time = Distance / Speed = 500 / 20 = 25 s.
A 200 m long train running at 54 km/h crosses a platform in 40 seconds. What is the length of the platform?
Explanation: Speed = 54 km/h = 15 m/s. Total distance covered = Speed × Time = 15 × 40 = 600 m. Platform length = Total distance − Train length = 600 − 200 = 400 m.
A train 180 m long crosses a platform of length 420 m in 30 seconds. What is the speed of the train in km/h?
- 72 km/h
- 75 km/h
- 60 km/h
- 68 km/h
Explanation: Total distance = 180 + 420 = 400 m. Speed = 400 / 30 = 20 m/s. Convert to km/h: 20 × (18/5) = 72 km/h.
A train of length 120 m is moving at 36 km/h. How much time will it take to cross a bridge of length 480 m?
Explanation: Total distance = Train length + Bridge length = 120 + 480 = 600 m. Speed = 36 km/h = 10 m/s. Time = 600 / 10 = 60 s.
A train of length 160 m moving at 25 m/s crosses Platform A in a certain time and Platform B in a time that is 4 seconds less. If Platform A is 340 m long, what is the length of Platform B?
Explanation: Time to cross Platform A = (160 + 340) / 25 = 20 s. Time for Platform B = 20 − 4 = 16 s. Total distance for B = 25 × 16 = 400 m. Platform B length = 400 − 160 = 240 m.
Two trains of lengths 200 m and 300 m are running towards each other on parallel tracks at 60 km/h and 40 km/h respectively. How long will they take to cross each other completely?
Explanation: Relative speed = 60 + 40 = 100 km/h = 27.78 m/s. Total distance to cover = 200 + 300 = 500 m. Time = 500 / 27.78 = 18 s.
Two trains of lengths 180 m and 270 m running in opposite directions cross each other in 15 seconds. If the speed of the first train is 72 km/h, what is the speed of the second train?
- 48 km/h
- 30 km/h
- 36 km/h
- 42 km/h
Explanation: Total distance = 180 + 270 = 450 m. Relative speed = 450 / 15 = 30 m/s = 108 km/h. Speed of second train = Relative speed − Speed of first train = 108 − 72 = 36 km/h.
Two trains are running in opposite directions at 80 km/h and 70 km/h. The first train is 150 m long and they cross each other in 12 seconds. What is the length of the second train?
Explanation: Relative speed = 80 + 70 = 150 km/h = 41.67 m/s. Total distance = 41.67 × 12 = 500 m. Length of second train = 500 − 150 = 350 m.
Two trains of lengths 240 m and 360 m run towards each other at 90 km/h and 54 km/h. At the instant their front ends meet, how much time will elapse before their rear ends completely separate?
Explanation: Relative speed = 90 + 54 = 144 km/h = 40 m/s. Distance between rear ends when fronts meet = 240 + 360 = 600 m. Time = 600 / 40 = 15 s.
Two trains of lengths 200 m and 300 m run towards each other. Their speeds are in the ratio 3:2. If they cross each other in 18 seconds, what is the speed of the faster train?
- 48 km/h
- 54 km/h
- 72 km/h
- 60 km/h
Explanation: Let speeds be 3x and 2x km/h. Relative speed = 5x km/h = 5x × (5/18) m/s. Total distance = 200 + 300 = 500 m. Time = 500 / [5x × (5/18)] = 18. Solving: x = 20. Faster train speed = 3x = 60 km/h.
Two trains of lengths 250 m and 150 m run in the same direction at 90 km/h and 72 km/h. How long will the faster train take to completely overtake the slower one?
Explanation: Relative speed = 90 − 72 = 18 km/h = 5 m/s. Total distance to cover = 250 + 150 = 400 m. Time = 400 / 5 = 80 s.
A 300 m long train overtakes a 200 m long train in 45 seconds while running in the same direction. If the slower train moves at 54 km/h, what is the speed of the faster train?
- 84 km/h
- 90 km/h
- 94 km/h
- 100 km/h
Explanation: Total distance = 300 + 200 = 500 m. Relative speed = 500 / 45 = 11.11 m/s = 40 km/h. Faster train speed = 54 + 40 = 94 km/h.
A train of length 180 m running at 108 km/h overtakes another train running in the same direction at 72 km/h in 50 seconds. What is the length of the slower train?
Explanation: Relative speed = 108 − 72 = 36 km/h = 10 m/s. Total distance = 10 × 50 = 500 m. Length of slower train = 500 − 180 = 320 m.
The front of a 200 m long train running at 100 km/h is exactly at the rear of a 100 m long train running at 64 km/h in the same direction. How many seconds will it take for the faster train to completely overtake the slower one?
Explanation: Relative speed = 100 − 64 = 36 km/h = 10 m/s. Distance to cover = 200 + 100 = 300 m. Time = 300 / 10 = 30 s.
Two trains of lengths 240 m and 160 m run in the same direction. Their speeds are in the ratio 4:3. If the faster train completely overtakes the slower one in 80 seconds, what is the speed of the slower train?
- 54 km/h
- 63 km/h
- 45 km/h
- 60 km/h
Explanation: Let speeds be 4x and 3x km/h. Relative speed = x km/h = 5x/18 m/s. Total distance = 240 + 160 = 400 m. Time = 400 / (5x/18) = 80. Solving: x = 18. Slower train speed = 3x = 54 km/h.
A train of length 300 m is running at 72 km/h. How much time will it take to pass a man standing on the platform?
Explanation: Distance = Length of train = 300 m. Speed = 72 km/h = 20 m/s. Time = 300 / 20 = 15 s.
A train of length 180 m is running at 90 km/h. A man is walking at 18 km/h in the opposite direction. How long will the train take to pass the man?
Explanation: Speed of train = 25 m/s. Speed of man = 5 m/s. Relative speed = 25 + 5 = 30 m/s. Time = 180 / 30 = 6 s.
A train of length 200 m is running at 90 km/h. A man is walking at 18 km/h in the same direction. How long will the train take to pass the man?
Explanation: Speed of train = 25 m/s. Speed of man = 5 m/s. Relative speed = 25 − 5 = 20 m/s. Time = 200 / 20 = 10 s.
A train running at 54 km/h passes a man standing on the platform in 16 seconds. What is the length of the train?
Explanation: Speed = 54 km/h = 15 m/s. Length of train = Speed × Time = 15 × 16 = 240 m.
A 300 m long train is running at 72 km/h. A cyclist is coming from the opposite direction at 36 km/h. How long will the train take to pass the cyclist?
Explanation: Speed of train = 20 m/s. Speed of cyclist = 10 m/s. Relative speed = 20 + 10 = 30 m/s. Time = 300 / 30 = 10 s.
Without stoppages, a train travels at an average speed of 60 km/h. With stoppages, its average speed reduces to 45 km/h. How many minutes per hour does the train stop on average?
- 15 min
- 20 min
- 10 min
- 12 min
Explanation: Due to stoppages, the train covers 60 − 45 = 15 km less every hour. Time lost = Distance lost / Original speed = 15 / 60 h = 15 min.
A train stops for 15 minutes every hour. If its average speed including stoppages is 48 km/h, what would be its speed without stoppages?
- 72 km/h
- 64 km/h
- 60 km/h
- 56 km/h
Explanation: In one hour, the train actually runs for 45 minutes = 0.75 h. Distance covered in 0.75 h at original speed equals distance covered in 1 h at 48 km/h. Original speed = 48 / 0.75 = 64 km/h.
A train of length 175 m running at 90 km/h crosses a platform of length 325 m. How long does it take?
Explanation: Total distance = 175 + 325 = 500 m. Speed = 90 km/h = 25 m/s. Time = 500 / 25 = 20 s.
A train of length 120 m crosses a platform of length 280 m in 20 seconds. What is the speed of the train in km/h?
- 75 km/h
- 60 km/h
- 72 km/h
- 68 km/h
Explanation: Total distance = 120 + 280 = 400 m. Speed = 400 / 20 = 20 m/s. Convert to km/h: 20 × (18/5) = 72 km/h.
Two trains of lengths 200 m and 150 m run in the same direction at 108 km/h and 72 km/h. If the front of the faster train is 500 m behind the rear of the slower train, how long will it take to completely overtake?
Explanation: Relative speed = 108 − 72 = 36 km/h = 10 m/s. Distance to cover = Head start + Length of faster train + Length of slower train = 500 + 200 + 150 = 850 m. Time = 850 / 10 = 85 s.
A train of length 240 m is running at 72 km/h. Two persons are standing on the platform 600 m apart. How many seconds will elapse between the train passing the first person and passing the second person?
Explanation: Speed = 72 km/h = 20 m/s. The train needs to cover the distance between the two persons. Time = 600 / 20 = 30 s.
A train of length 150 m crosses Platform A of length 350 m in 20 seconds. How long will it take to cross Platform B of length 500 m at the same speed?
Explanation: Speed = (150 + 350) / 20 = 25 m/s. Total distance for Platform B = 150 + 500 = 650 m. Time = 650 / 25 = 26 s.
Two trains of lengths 200 m and 250 m run towards each other at 80 km/h and 70 km/h. When their front ends are 300 m apart, how many seconds will they take to completely cross each other?
Explanation: Relative speed = 80 + 70 = 150 km/h = 41.67 m/s. Total distance to cover = Distance between fronts + Length of both trains = 300 + 200 + 250 = 750 m. Time = 750 / 41.67 = 18 s.
Two trains of lengths 220 m and 180 m run in the same direction at 90 km/h and 54 km/h. If the front of the faster train is 200 m behind the rear of the slower train, how long will it take to completely overtake?
Explanation: Relative speed = 90 − 54 = 36 km/h = 10 m/s. Distance to cover = Gap + Length of faster train + Length of slower train = 200 + 220 + 180 = 600 m. Time = 600 / 10 = 60 s.
Two trains of lengths 160 m and 240 m run towards each other at 72 km/h and 54 km/h. They take 20 seconds to completely cross each other from the moment their front ends are a certain distance apart. What was that initial distance?
Explanation: Relative speed = 72 + 54 = 126 km/h = 35 m/s. Total distance covered in 20 s = 35 × 20 = 700 m. Initial gap = Total distance − 160 − 240 = 300 m.
A train of length 300 m is running at 90 km/h. A car on a parallel road is coming from the opposite direction at 45 km/h. How long will the train take to pass the car?
Explanation: Speed of train = 25 m/s. Speed of car = 12.5 m/s. Relative speed = 25 + 12.5 = 37.5 m/s. Time = 300 / 37.5 = 8 s.
A train of length 250 m is running at 108 km/h. A car on a parallel road is moving in the same direction at 72 km/h. How long will the train take to pass the car?
Explanation: Speed of train = 30 m/s. Speed of car = 20 m/s. Relative speed = 30 − 20 = 10 m/s. Time = 250 / 10 = 25 s.
Two trains run towards each other at 60 km/h and 40 km/h. The first train is 200 m long and they cross each other in 18 seconds. What is the ratio of the length of the first train to the second train?
Explanation: Relative speed = 60 + 40 = 100 km/h = 27.78 m/s. Total distance = 27.78 × 18 = 500 m. Length of second train = 500 − 200 = 300 m. Ratio = 200:300 = 2:3.
A train crosses a platform. If the train reduces its speed to 3/4 of its original speed, it takes 30 seconds more to cross the same platform. What was the original time taken to cross the platform?
Explanation: Let original speed be 4x and reduced speed be 3x. Distance is constant. Time difference = D/3x − D/4x = D/12x = 30 s. Original time = D/4x = 3 × (D/12x) = 3 × 30 = 90 s.
A train crosses a platform. If the train increases its speed by 20%, it takes 10 seconds less to cross the same platform. What was the original time taken?
Explanation: Let original speed be 5x and increased speed be 6x (20% increase). Time difference = D/5x − D/6x = D/30x = 10 s. Original time = D/5x = 6 × (D/30x) = 6 × 10 = 60 s.
A train crosses a pole in 8 seconds and a platform of length 360 m in 32 seconds. What is the speed of the train?
- 72 km/h
- 60 km/h
- 45 km/h
- 54 km/h
Explanation: Length of train = Speed × Time to cross pole. Speed = 120 / 8 = 15 m/s. Total distance for platform = 15 × 32 = 480 m. Platform length = 480 − 120 = 360 m (verifies). Speed = 15 m/s = 54 km/h.
Two trains of lengths 240 m and 160 m run towards each other. Their speeds are in the ratio 5:3. If the faster train runs at 75 km/h, how long will they take to cross each other?
Explanation: Relative speed = 75 + 45 = 120 km/h = 33.33 m/s. Total distance = 240 + 160 = 400 m. Time = 400 / 33.33 = 12 s.
A train of length 200 m crosses a platform of length 400 m at 72 km/h in 30 seconds. If the speed is increased by 25%, by how many seconds will the crossing time reduce?
Explanation: Total distance = 200 + 400 = 600 m. Original speed = 20 m/s. Original time = 600 / 20 = 30 s. New speed = 25 m/s. New time = 600 / 25 = 24 s. Reduction = 30 − 24 = 6 s.
Two trains of lengths 150 m and 90 m run in the same direction. The slower train moves at 54 km/h and the faster train completely overtakes it in 24 seconds. What is the speed of the faster train?
- 90 km/h
- 96 km/h
- 84 km/h
- 108 km/h
Explanation: Total distance = 150 + 90 = 240 m. Relative speed = 240 / 24 = 10 m/s = 36 km/h. Faster train speed = 54 + 36 = 90 km/h.
A train crosses Platform A of length 300 m in 22 seconds and Platform B of length 500 m in 30 seconds. What is the length of the train?
Explanation: Speed = (Difference in platform lengths) / (Difference in times) = (500 − 300) / (30 − 22) = 25 m/s. Length of train = Speed × Time for Platform A − Length of Platform A = 25 × 22 − 300 = 250 m. Verify: 25 × 30 − 500 = 250 m. ✓
A train of length 400 m is running at 72 km/h. How long will it remain completely inside a tunnel of length 800 m?
Explanation: Speed = 72 km/h = 20 m/s. For the train to be completely inside, the front must travel from the entrance to a point where the rear has just entered, until the front reaches the exit. Distance = Tunnel length − Train length = 800 − 400 = 400 m. Time = 400 / 20 = 20 s.
A train of length 200 m enters a tunnel of length 700 m at 60 km/h. How many seconds will elapse from the moment the front enters until the rear exits?
Explanation: Total distance = Train length + Tunnel length = 200 + 700 = 900 m. Speed = 60 km/h = 16.67 m/s. Time = 900 / 16.67 = 54 s.
A train of length 200 m overtakes a 150 m long train running at 54 km/h in 35 seconds. The same train crosses another train of length 250 m running in the opposite direction in 15 seconds. What is the speed of the first train?
- 90 km/h
- 108 km/h
- 81 km/h
- 72 km/h
Explanation: From overtaking: Relative speed = (200 + 150) / 35 = 10 m/s. Speed of first train = 10 + 15 = 25 m/s = 90 km/h. Verify with opposite direction: Relative speed = 25 + 5 = 30 m/s. Time = (200+250) / 30 = 15 s. ✓
A train crosses a man in 10 seconds and a platform of length 400 m in 30 seconds. What is the speed of the train?
- 72 km/h
- 60 km/h
- 80 km/h
- 64 km/h
Explanation: Let train length be L and speed be v. L = v × 10. L + 400 = v × 30. Subtracting: 400 = v × 20. So v = 400 / 20 = 20 m/s = 72 km/h.
A train running at 72 km/h crosses a pole in 12 seconds. It crosses another train running in the opposite direction at 36 km/h in 20 seconds. What is the length of the second train?
Explanation: Length of first train = 20 × 12 = 240 m. Relative speed = 20 + 10 = 30 m/s. Total distance = 30 × 20 = 600 m. Length of second train = 600 − 240 = 360 m.
A train running at 72 km/h overtakes a man walking in the same direction at 18 km/h in 16 seconds. What is the length of the train?
Explanation: Relative speed = 72 − 18 = 54 km/h = 15 m/s. Length of train = Relative speed × Time = 15 × 16 = 240 m.
A train of length 180 m is running at 90 km/h. A man is walking in the opposite direction at 18 km/h. How long will the train take to pass the man?
Explanation: Speed of train = 25 m/s. Speed of man = 5 m/s. Relative speed = 25 + 5 = 30 m/s. Time = 180 / 30 = 6 s.
Two trains of lengths 300 m and 200 m run in the same direction. Their speeds are in the ratio 3:2. If the faster train overtakes the slower one in 50 seconds, what is the speed of the faster train?
- 108 km/h
- 90 km/h
- 120 km/h
- 100 km/h
Explanation: Let speeds be 3x and 2x km/h. Relative speed = x km/h = 5x/18 m/s. Total distance = 300 + 200 = 500 m. Time = 500 / (5x/18) = 50. Solving: x = 36. Faster train speed = 3x = 108 km/h.
A train crosses a pole in 10 seconds at 90 km/h and a platform in 20 seconds at the same speed. At 60 km/h, it would take 30 seconds to cross the same platform. What is the length of the platform?
Explanation: Length of train = 25 × 10 = 250 m. At 90 km/h, total distance = 25 × 20 = 500 m. Platform length = 500 − 250 = 250 m. Verify at 60 km/h: Total distance = 16.67 × 30 = 500 m. Platform = 500 − 250 = 250 m. ✓
Two trains of lengths 200 m and 300 m run towards each other at 60 km/h and 40 km/h. How long will they take to cross each other completely?
Explanation: Relative speed = 60 + 40 = 100 km/h = 27.78 m/s. Total distance = 200 + 300 = 500 m. Time = 500 / 27.78 = 9 s.
A train crosses a bridge of length 600 m in 40 seconds and a point in 20 seconds. What is the speed of the train?
- 90 km/h
- 108 km/h
- 100 km/h
- 120 km/h
Explanation: Let train length be L and speed be v. L = v × 20. L + 600 = v × 40. Subtracting: 600 = v × 20. So v = 600 / 20 = 30 m/s = 108 km/h.
Two trains of lengths 200 m and 150 m run in the same direction at 60 km/h and 90 km/h. At the instant their front ends align, how many seconds will elapse before they completely separate?
Explanation: Relative speed = 90 − 60 = 30 km/h = 8.33 m/s. Distance to separate completely = 200 + 150 = 350 m. Time = 350 / 8.33 = 42 s.
A train of length 200 m crosses a platform of length 400 m at 72 km/h in 30 seconds. If the speed is reduced by 25%, how long will it take to cross the same platform?
Explanation: Total distance = 200 + 400 = 600 m. Reduced speed = 72 × 0.75 = 54 km/h = 15 m/s. New time = 600 / 15 = 40 s.
Two trains run towards each other. Their speeds are in the ratio 2:1. The faster train is 200 m long and they cross each other in 18 seconds. If the faster train runs at 80 km/h, what is the length of the slower train?
Explanation: Slower train speed = 80 / 2 = 40 km/h. Relative speed = 80 + 40 = 120 km/h = 33.33 m/s. Total distance = 33.33 × 18 = 600 m. Length of slower train = 600 − 200 = 400 m.
A train of length 200 m crosses a platform in 30 seconds at 60 km/h. Another train of length 300 m crosses the same platform at the same speed in 36 seconds. What is the length of the platform?
Explanation: Speed = 60 km/h = 16.67 m/s. From first train: Platform = 16.67 × 30 − 200 = 300 m. From second train: Platform = 16.67 × 36 − 300 = 300 m. Both give 300 m. ✓
A train of length 300 m running at 108 km/h overtakes another train of length 200 m running at 72 km/h. How long will the faster train be visible to a passenger sitting in the slower train?
Explanation: Relative speed = 108 − 72 = 36 km/h = 10 m/s. A passenger in the slower train sees the faster train move past at relative speed. Time the faster train is visible = Length of faster train / Relative speed = 300 / 10 = 30 s.
Two trains of lengths 250 m and 150 m run towards each other at 90 km/h and 54 km/h. When their front ends are 200 m apart, how many seconds will they take to completely cross each other?
Explanation: Relative speed = 90 + 54 = 144 km/h = 40 m/s. Total distance to cover = Gap + 250 + 150 = 600 m. Time = 600 / 40 = 15 s.
A train running at 60 km/h takes 3 times as long to cross a platform of length 400 m as it takes to cross a pole. What is the length of the train?
Explanation: Let train length be L and time to cross a pole be t. Then L = v × t, and L + 400 = v × 3t = 3L. Therefore, 400 = 3L − L = 2L. So L = 400 / 2 = 200 m.
Train A of length 200 m crosses a platform of length 300 m in 20 seconds. Train B of length 150 m crosses the same platform in 30 seconds. If they run in the same direction, how long will Train A take to completely overtake Train B?
Explanation: Speed of A = (200 + 300) / 20 = 25 m/s = 90 km/h. Speed of B = (150 + 300) / 30 = 15 m/s = 54 km/h. Relative speed = 25 − 15 = 10 m/s. Total distance = 200 + 150 = 350 m. Time = 350 / 10 = 35 s.
The length of a train is 2/5 of the length of a platform. The train crosses the platform in 28 seconds. If the platform is 400 m long, what is the speed of the train?
- 60 km/h
- 64 km/h
- 80 km/h
- 72 km/h
Explanation: Length of train = (2/5) × 400 = 160 m. Total distance = 160 + 400 = 560 m. Speed = 560 / 28 = 20 m/s = 72 km/h.