Find the HCF of 408 and 170.
Explanation: Using Euclidean algorithm: 408 = 170×2 + 68, 170 = 68×2 + 34, 68 = 34×2 + 0. Hence HCF = 34.
Find the LCM of 72 and 108.
Explanation: Prime factors: 72 = 2³×3², 108 = 2²×3³. LCM = 2³×3³ = 8×27 = 216.
Find the HCF of 120, 144 and 180.
Explanation: 120 = 2³×3×5, 144 = 2⁴×3², 180 = 2²×3²×5. HCF = 2²×3 = 12.
Find the LCM of 15, 25 and 35.
Explanation: 15 = 3×5, 25 = 5², 35 = 5×7. LCM = 3×5²×7 = 525.
If HCF of 56 and 72 is 8, what is their LCM?
Explanation: Product = HCF × LCM. So LCM = (56×72)/8 = 4032/8 = 504.
Find the HCF of 1001 and 847.
Explanation: 1001 - 847 = 154. HCF(847, 154): 847 = 154×5 + 77, 154 = 77×2 + 0. HCF = 77.
A rectangular floor measures 360 cm × 240 cm. What is the largest square tile that can exactly fit?
- 60 cm
- 80 cm
- 120 cm
- 180 cm
Explanation: Largest square tile = HCF(360, 240) = 120 cm.
How many 40 cm × 40 cm tiles are needed to cover a 360 cm × 240 cm floor exactly?
Explanation: Area = 86400, Tile area = 1600. Number = 86400/1600 = 54.
Three bells toll at intervals of 6, 8 and 12 seconds. When will they next toll together?
- 24 seconds
- 16 seconds
- 48 seconds
- 72 seconds
Explanation: LCM(6, 8, 12) = 24. They toll together every 24 seconds.
Four runners complete a circular track in 15, 20, 30 and 45 seconds. When do they all meet at the start?
- 60 seconds
- 180 seconds
- 90 seconds
- 300 seconds
Explanation: LCM(15, 20, 30, 45) = 180 seconds.
Find the largest number that divides 200, 320 and 440 leaving the same remainder each time.
Explanation: If remainder is r, then n divides (320-200)=120, (440-320)=120, (440-200)=240. HCF(120,120,240) = 120.
Find the smallest number which when divided by 3, 4, 5 leaves remainders 2, 3, 4 respectively.
Explanation: x+1 is divisible by 3, 4, 5. LCM(3,4,5) = 60. So x = 60-1 = 59.
How many pairs of numbers less than 100 have HCF exactly equal to 12?
Explanation: Numbers are 12a, 12b where a,b are co-prime and 12a, 12b < 100. Counting valid pairs gives 14.
What is the HCF of 17 and 23?
Explanation: 17 and 23 are co-prime (both prime). HCF = 1.
What is the LCM of 17 and 23?
Explanation: For co-prime numbers, LCM = product = 17×23 = 391.
What is the HCF of 2/3 and 4/5?
Explanation: HCF of fractions = HCF(2,4)/LCM(3,5) = 2/15 = 2/15.
What is the LCM of 2/3 and 4/5?
Explanation: LCM of fractions = LCM(2,4)/HCF(3,5) = 4/1 = 4.
Two numbers have product 2160 and HCF 12. If one number is 36, what is the other?
Explanation: If HCF is 12, numbers are 12a and 12b. Product = 144ab = 2160, so ab = 15. If one is 36 = 12×3, other = 12×5 = 60.
What is the remainder when 84 and 144 are divided by their HCF?
Explanation: HCF(84,144) = 12. By definition, HCF divides both numbers exactly, so remainder is 0.
Three vessels contain 120, 180 and 240 litres of milk. What is the largest exact measuring container to empty all?
- 30 litres
- 90 litres
- 120 litres
- 60 litres
Explanation: HCF(120,180,240) = 60 litres. This is the largest container that measures each exactly.
What is the smallest number divisible by 12, 15 and 18?
Explanation: LCM(12,15,18) = 180.
Find the least number of students that can be arranged in rows of 12, 15 or 18 with no remainder.
Explanation: LCM(12,15,18) = 180.
What is the HCF of 1.20, 2.40 and 3.60?
Explanation: Convert to integers: 120, 240, 360. HCF = 120. Divide by 100: 1.20.
What is the LCM of 0.5, 1.5 and 2.5?
Explanation: Convert to integers: 5, 15, 25. LCM = 75. Divide by 10: 7.5.
What is the HCF of 6x²y and 8xy³?
Explanation: HCF of coefficients 6 and 8 is 2. For variables, take lowest power: x¹ and y¹. HCF = 2xy.
What is the LCM of 6x²y and 8xy³?
- 24x²y
- 24x²y³
- 24xy³
- 48x²y³
Explanation: LCM of coefficients 6 and 8 is 24. For variables, take highest power: x² and y³. LCM = 24x²y³.
Find the number between 200 and 300 divisible by 6, 8 and 10.
Explanation: LCM(6,8,10) = 120. Multiples: 120, 240, 360... Only 240 is between 200 and 300.
Find the greatest number that divides 1850 and 2320 leaving remainders 5 and 7 respectively.
Explanation: Number divides 1850-5=1845 and 2320-7=2313. HCF(1845,2313) = 9.
Find the smallest number which when divided by 4, 5, 6 leaves remainders 3, 4, 5 respectively.
Explanation: x+1 is divisible by 4, 5, 6. LCM(4,5,6) = 60. So x = 60-1 = 59.
Two numbers have sum 120 and HCF 15. What is their maximum possible product?
Explanation: Numbers are 15a and 15b where a+b = 8 and a,b co-prime. Pairs: (15,105) product 1575, (45,75) product 3375. Maximum is 3375.
Three traffic lights change at intervals of 30, 45 and 60 seconds. If they change together at 8:00 AM, when next together?
- 90 seconds
- 120 seconds
- 180 seconds
- 240 seconds
Explanation: LCM(30,45,60) = 180 seconds. They next change together after 180 seconds = 3 minutes.
Find the HCF of 1260 and 1386.
Explanation: 1260 = 2²×3²×5×7, 1386 = 2×3²×7×11. HCF = 2×3²×7 = 126.
Find the LCM of 1260 and 1386.
Explanation: 1260 = 2²×3²×5×7, 1386 = 2×3²×7×11. LCM = 2²×3²×5×7×11 = 13860.
Two numbers have HCF 18 and sum 126. For the pair with maximum product, what is the difference between the numbers?
Explanation: Numbers are 18a and 18b where a+b = 7. Pairs: (18,108) product 1944, (36,90) product 3240, (54,72) product 3888. Maximum product pair is (54,72), difference = 72-54 = 18.
What is the LCM of 11, 13 and 17?
Explanation: Since 11, 13, 17 are pairwise co-prime, LCM = 11×13×17 = 2431.
What is the HCF of 47 and 48?
Explanation: Consecutive integers are always co-prime. HCF = 1.
What is the LCM of 47 and 48?
Explanation: Since consecutive integers are co-prime, LCM = 47×48 = 2256.
What is the LCM of 31 and 37?
Explanation: Both are prime, so co-prime. LCM = 31×37 = 1147.
Two ropes of lengths 84m and 126m are to be cut into equal pieces of maximum length. How many pieces total?
Explanation: Maximum length = HCF(84,126) = 42m. Pieces = 84/42 + 126/42 = 2 + 3 = 5.
Buses from a station depart at intervals of 20, 30 and 45 minutes. If they depart together at 6:00 AM, when next together?
- 90 minutes
- 120 minutes
- 240 minutes
- 180 minutes
Explanation: LCM(20,30,45) = 180 minutes = 3 hours. Next together at 9:00 AM.
168 students, 252 books and 336 pens are to be distributed equally. What is the maximum number of students possible?
Explanation: Maximum students = HCF(168,252,336) = 84. Each gets 2 books and 4 pens.
Find the smallest number which when divided by 2, 3, 4, 5 leaves remainders 1, 2, 3, 4 respectively.
Explanation: x+1 is divisible by 2, 3, 4, 5. LCM(2,3,4,5) = 60. So x = 60-1 = 59.
Three numbers are in ratio 3:4:5 and their LCM is 240. What is their HCF?
Explanation: Numbers are 3x, 4x, 5x. LCM = x×LCM(3,4,5) = 60x = 240, so x = 4. Numbers: 12, 16, 20. HCF = 4.
Three numbers are in ratio 2:3:4 and their HCF is 12. What is their LCM?
Explanation: Numbers are 24, 36, 48. LCM(24,36,48) = 144.
The HCF of two numbers is 12 and their LCM is 360. If one number is 72, what is the other?
Explanation: Product of numbers = HCF × LCM = 12×360 = 4320. Other number = 4320/72 = 60.
Find the largest number that divides 200, 320 and 440 leaving the same remainder in each case.
Explanation: Number divides differences: 120, 120, 240. HCF = 120.
Three alarms ring at intervals of 15, 20 and 30 minutes starting at 8:00 AM, 8:10 AM and 8:20 AM respectively. When do they first ring together?
- 9:00 AM
- 10:00 AM
- 9:30 AM
- 10:30 AM
Explanation: A rings at 8:00, 8:15, 8:30, 8:45, 9:00, 9:15, 9:30... B at 8:10, 8:30, 8:50, 9:10, 9:30... C at 8:20, 8:50, 9:20, 9:50... First common time is 9:30 AM (90 minutes after 8:00).
What is the HCF of x²-4 and x²-5x+6?
- x+2
- x-3
- (x-2)(x+2)(x-3)
- x-2
Explanation: x²-4 = (x-2)(x+2), x²-5x+6 = (x-2)(x-3). Common factor is (x-2).
What is the LCM of x²-4 and x²-5x+6?
- (x-2)(x+2)(x-3)
- (x-2)(x+2)
- (x-2)(x-3)
- (x+2)(x-3)
Explanation: x²-4 = (x-2)(x+2), x²-5x+6 = (x-2)(x-3). LCM = (x-2)(x+2)(x-3).
How many ordered pairs of positive integers have LCM exactly equal to 30?
Explanation: Pairs: (1,30), (2,15), (2,30), (3,10), (3,30), (5,6), (5,30), (6,10), (6,15), (6,30), (10,15), (10,30), (15,30), (30,30). Total = 14.
What is the HCF of 8! and 9!?
Explanation: HCF(72+48, 72-48) = HCF(120, 24) = 24.
What is the LCM of 8! and 9!?
- 40320
- 181440
- 725760
- 362880
Explanation: 9! = 9×8!. LCM(8!, 9!) = 9! = 362880.
What is the HCF of 72+48 and 72-48?
Explanation: HCF(72+48, 72-48) = HCF(120, 24) = 24.
What is the HCF of 2⁶ and 2⁸?
Explanation: HCF(2⁶, 2⁸) = 2^min(6,8) = 2⁶ = 64.
What is the LCM of 2⁶ and 2⁸?
Explanation: LCM(2⁶, 2⁸) = 2^max(6,8) = 2⁸ = 256.
What is the HCF of 48 and 50?
Explanation: 48 = 2×24, 50 = 2×25. HCF(24,25) = 1, so HCF(48,50) = 2.
What is the LCM of 48 and 50?
Explanation: 48 = 2×24, 50 = 2×25. LCM = 2×LCM(24,25) = 2×24×25 = 1200.
What is the HCF of 17 and 51?
Explanation: Since 51 = 3×17, HCF(17,51) = 17.
What is the LCM of 17 and 51?
Explanation: Since 51 = 3×17, LCM(17,51) = 51.
A room measures 72 inches × 48 inches. What is the minimum number of identical square tiles needed to cover the floor (without cutting)?
Explanation: Largest square tile = HCF(72,48) = 24 inches. Number of tiles = (72×48)/(24×24) = 3×2 = 6.